Finding the percentage - Hacker Rank Solution

 Problem Statement :

The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

Example:

     marks key: value pairs are

    'alpha': [20,30,40]

    'beta': [30,50,70]

    query_name = 'beta'

The query_name is 'beta'. beta's average score is (20+50+70)/3 = 50.

Input Format:

 The first line contains the integer n, the number of students' records. The next n lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.

Constraints:

            0<=n<=10

            0<=marks[i]<=100

            length of marks array=3

Output Format:

 Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

Code:

if __name__ == '__main__':
    n = int(input())
    student_marks = {}
    for _ in range(n):
        line = input().split()
        name, scores = line[0], line[1:]
        scores = map(float, scores)
        student_marks[name] = scores
    query_name = input()
    marks=0
    for i in student_marks[query_name]:
        marks=marks+i
    avg=marks/3
    print("%.2f"%avg)